6. For DATEDIFF: date_or_time_expr1 and date_or_time_expr2 can be a date, time, or timestamp. SELECT floor ( months_between ( date_1, date_2 )/12) floor_years_between FROM employee. 00. 2903225806. Therefore try to subtract the two dates to get the difference in days. 0. LukeH LukeH. Extract a value of a date time field e. for example Feb-15th to Mar-15th is a month. If you omit fmt, then date is rounded to the. It returns a whole month (no fraction) if both dates have the same day-of-month or. datediff() is not giving tHe result as I am working in Oracle. You could simply minus the years but quarters would be. In Oracle, MONTHS_BETWEEN(date1, date2) function returns the number of months between two dates as a decimal number. – user330315. DAYS(date2 - date1). g. SQL Retrieve the records of previous month. In short. lastModified - w. 2 Answers. Viewed 516 times 0 Everyone, the table relationship diagram for the database is the below one. As another option you could use the months_between () function, and manipulate the value that gives you into the three parts. Converts one date format to a new format and returns the result. Add a number of months (n) to a date and return the same day which is n of months away. Also, to get the end date for the quarter, just use: select dateadd (quarter, datediff (quarter, 0, SomeDate)+1,0) -1. In SQL, we can add or subtract days, months, or years to a date by using the DATEADD function. DayCount) How can I do this in SQL (needs to work in MSSQL Server and Oracle)?Month and day of the year don’t appear to be factored into the equation. If this query is executed between December 26 and December 31, you'll still. A note on Databricks: Databricks additionally supports a separate DATEDIFF function that takes only two arguments: a start date and an end date. Asked 8 years, 2 months ago. Click on the function name to jump to a discussion of that function. date_to) - (DATEDIFF(WK, evnt. 15 between 2 values that are 1 year, 1 month and 15 days apart. Exhibit A: John Doe has served since Feb 10, 2016. For example, from 2/10 to 3/10 is considered one month, and from 2/10 to 3/15 is also considered one month. The interval of time to use to calculate the difference between date1 and date2. The data type both are Date, one sample data . HEH! One big difference you’ll find is that adding or subtracting two date values in Oracle leaves you with a number, not a date. date_from, evnt. first weeks into oracle. CASE WHEN a. It should have been DATEDIFF NOT DATEADD with respect to the WEEK parameter. EXTRACT the number of years from the interval. sql. Each Standard calendar week is. i need to find the difference of two dates as the number of months: find the last day of the month of both the dates. 2425. I have the following query that I'm trying to get the length of service of a person at their company. 0. The SQL DATEDIFF() function is an in-built function in SQL that is used to return the difference (as a signed integer value) between two dates or times. dividing by 365. Currently I am only returning 1. SELECT DATEDIFF (YY, DateOfBirth, GETDATE ()) - CASE WHEN RIGHT (CONVERT (VARCHAR (6), GETDATE (), 12), 4) >= RIGHT (CONVERT (VARCHAR (6), DateOfBirth, 12), 4) THEN 0 ELSE 1 END AS AGE. Use DATEADD and DATEDIFF() function together in SQL query. 8. date2 Syntax. Syntax @DATEDIFF (' difference ', ' date ', ' date ') difference. It means that the DATEPART function returns the number of times the boundary between two units is crossed. SELECT datediff ( TIMESTAMP '1981-04-01 10:11:13', TIMESTAMP '2022-04-03 17:48:09') as diff FROM DUAL; Outputs: DIFF. I have a creation date column in the table. How to calculate years of experience from date_of_hiring to till date in months of an employee using sql query. 37. MySQL DATEDIFF: Calculating weeks, months, or years between two dates. This will return an interval that may look something like “1 year 2 months 3 days”. February 28 and March 31) can lead to unintuitive behavior; specifically, increasing the first date in the pair does not always increase the output value. Also, according to Oracle's documentation LAST_DAY returns a DATE. Sorted by: 3. DATEDIFF Examples Using All Options. Kindly help on this. As you can see the EOMONTH function takes into account leap year. Datediff (cast ('2020-08-01' as Date),Cast ('2020-07-31' as Date)) => 1. For example, adding three months or 12 days to a starting date. The datediff function returns the difference between two specified dates in the time units that you specify: years, quarters, months, weeks, days, hours, minutes, or seconds. Share. NEXT_MONTH: Returns the first day of the next month after the specified date. A numeric value is returned. subtract and give the difference in number of months. So, it starts with RIGHT(“00”. Introduction. It can be used to do date math as well. , SYSDATE - pr. 6. 1. 11. Compare dates problems. 25 = 0. In SQL Server 2012 you can use EOMONTH (Transact-SQL) to get the last day of the month and then you can use DAY (Transact-SQL) to get the number of days in the month. . SELECT * FROM EmployeeAttendance WHERE DateJoined BETWEEN '2021-01-01' AND '2022-12-31'; This query will return all employees who joined between January 1, 2021, and December 31, 2022. You have to cast it first, using to_date: select to_date ('2000-01-01', 'yyyy-MM-dd') - to_date ('2000-01-02', 'yyyy-MM-dd'). select *, cast ( (cast (begin_date as date) - cast (end_date as date) YEAR) as decimal (3,2)) AS year_diff from x. 2. Modified 1 year, 3 months ago. 3. For ex. The difference between the specified dates. DECLARE @ADate DATETIME SET @ADate = GETDATE () SELECT DAY (EOMONTH (@ADate)) AS DaysInMonth. As shown clearly in the result, because 2016 is the leap year, the difference in days between two dates is 2×365 + 366 = 1096. count the number of elapsed time, taking care of daylight savings: day+1 - day = 1 = 24h (but using midnight time and daylight savings it could be 0 day and 23h)Find Difference Between two dates in YEARS with Oracle. DATEDIFF. Delaying Execution. The first one involves getting the difference in days and then converting it to 'x year y month z days'. Syntax The syntax for the MONTHS_BETWEEN function in Oracle/PLSQL is: MONTHS_BETWEEN ( date1, date2 ) Parameters or Arguments date1 The first date used to calculate the number of months between. SS: 差異を秒数で計算します。. I have a table where PurchasedDate is maintained. CREATE OR REPLACE FUNCTION datediff (p_what IN VARCHAR2, p_d1 IN DATE, p_d2 IN DATE) RETURN NUMBER /* Updated to reflect current database and PL/SQL functionality */ AS BEGIN RETURN (p_d2 - p_d1) * CASE UPPER (p_what) WHEN 'SS' THEN 24 * 60 * 60 WHEN 'MI' THEN 24 * 60 WHEN 'HH' THEN 24 ELSE NULL END; END;SELECT months_between ( date_1, date_2 )/12 years_between FROM employee. Factor by 24 to get hours, 24*60 to get minutes, 24*60*60 to get seconds (that's as small as dates go). AT TIME ZONE. 25) This seems to be another common approach - and was also given in a comment on my question. For a baby born 28-Feb-17, properly calculated they turn 1 years old on 28-Feb-18 - their next birthday. DATEDIFF SQL Server function. For the last row return the calculated date. Select DATEDIFF (MM,0,GETDATE ()) Output - 1374, If getdate () output is "2014-07-23 19:33:46. Asked 11 years, 5 months ago. For example, this function returns 1. =DATEDIFF ("d", Fields!startDate. Viewed 4k times 1 I have a table with below structure. TIMESTAMP Functions. For example, using the standard SCOTT. EXECUTION_DATE, EXEC_DIFF 01-FEB-13, 1 31-JAN-13, 2 30-JAN-13, 2. hourBegin, a. この番号を取得するには、次のいずれかの関数を使用: Today ()、TodateEx ()、GetFirstDate ()、GetLastDate ()、DateRoll ()。. Funciones comúnmente utilizadas de Oracle: DateDiff devuelve una función personalizada para el intervalo entre dos fechas (Por supuesto, hay otros métodos para lograr, en ORACLE los tipos de fechas se pueden comparar directamente, y finalmente dar ejemplos de métodos). Let’s see a few examples of SQL subtract date from the DATEADD function: In the below example, we are adding one month to the existing date ‘20220730’. 2425. MANAGER_ID, PROJECTED_DATE. Currently, my code just returns zero on the right side of the decimal place. You've told it to compare the. SELECT DISTINCT Test, FIRST_VALUE (CONVERT(DATE, datetime)) OVER (ORDER BY datetime DESC) StartDate,. Then it calculates the number of months that have passed until your given date (@test) by fours steps: 1. Get the number of months between two dates. Oracle/PLSQL: MONTHS_BETWEEN Function 2. 092000000 AM format. DateGroup. WHen I do. I am trying to create a new column that will show the age of the person on the date that they took up the membership. Oracle and MySQL support the SQL92 function EXTRACT, as in EXTRACT(MONTH FROM whn). How To turn a string with "pipe-separated" values into individual rows in Oracle PL/SQL. 1 + TRUNC (InstallDate) - TRUNC (InstallDate, 'IW') get 1 for mondays to 7 for sunday. Each day is 1 integer. If you like this article or if you have some. dividing by 365. How to unite two columns of date + time for datediff - Oracle sql. DateDiff(“m”, Fields! starting date. Taking example 1, Oracle is telling me that 3rd Feb was a longer time ago than Informatica is telling me it is. Modified 8 years, 2 months ago. Also, you need to put your dates into single quotes: use '2-2-2011' instead of simply 2-2-2011. DATEDIFF does not guarantee that the full number of the specified time units passed between 2 datetime values: -- Get difference in hours between 8:55 and 11:00 SELECT DATEDIFF (hh, '08:55', '11:00'); -- Returns 3 although only 2 hours and 5 minutes passed between times -- Get difference in months between Sep 30, 2011 and Nov 02, 2011. PROJECT_TYPE, PROJECT. expression1: This is a datetime expression you’ll substract expression2 from. Also, you can check this for minutes : Oracle : how to subtract two dates and get minutes of the result. Getting the months and years between two dates using Datediff There is a round up issue with the Datediff function. In SQL Server, there is a function datediff with datepart 'q'/quarter which behaves as follows :--select datediff(q,'03-30-2005','04-01-2005') will return 1 datediff(q,start date,end date) i. SQR for PeopleSoft provides an extensive set of date edit masks. Note that SQL Server DATEDIFF(month, date2, date1) function does not return exactly the same result, and you have to use an user-defined function if you need to fully emulate the Oracle MONTHS_BETWEEN function (see. Table 9. Viewed 20k times. This function is not sensitive to the NLS_CALENDAR session parameter. The week (wk, ww) datepart reflects changes made to SET DATEFIRST. for the month differnce the standard sql is DATEDIFF, in this function you must pass 3 params, if you must calculate the difference from 2 columns, c1 and c2, you must do this query SELECT DATEDIFF(month,c1 , c2) FROM T WHERE. If IsDate (startdate) and IsDate (enddate) Then. The system calculates the number of complete months between given dates. 2. Modified 8 years ago. This is from my own library, will return the difference of months between two dates. 0. For example: Todays date: Jun 13, 2017. then the following should be the result. Follow. Consider SQL Server function to calculate the difference between 2 dates in months: SQL Server : -- Difference between Oct 02, 2011 and Jan 01, 2012 in months SELECT DATEDIFF ( month, '2011-10-02', '2012-01-01') ; -- Result: 3. Viewed 14k times 2 I'm looking to get total number of days including the Start Date and End Date, some examples below:. id (SELECT SUM(DATEDIFF(HOUR, a. Value)/30. 5 days to a given date. Date. 4 Answers. SELECT months_between ( date_1, date_2 )/12 years_between FROM employee. g. DateDiff is use d to calculate the length of time between two dates. The first day of the year is 1. – user330315. The days are in two different, adjacent months, so the answer is 1 month difference. I can get these two dates from the database in 07-JUN-12 04. I was given code via an SR but it doesn't work (I'm able to save the code but when I try to look at the sample data, it just says "error"). However, The. Improve this answer. ) The dates and their formats are separated by a comma (,) and are defined in the Data field of the. 1 - Find the total months count till today's date using DATEDIFF function -. NEW_TIME (date, timezone1, timezone2) Timestamp. DATEDIFF() Returns the difference between the two dates. Viewed 32k times. Sum (r => EF. create or replace FUNCTION DATEDIFF ( P_TYPE_DATE IN VARCHAR2 , P_START_DATE IN TIMESTAMP , P_END_DATE IN TIMESTAMP ) RETURN NUMBER AS v_Result NUMBER := -1; BEGIN IF. I know it exists in SQL Server. The first one involves getting the difference in days and then converting it to 'x year y month z days'. The idea is to find how many years, months, and days they have served there. The datediff function returns the difference between two specified dates in the time units that you specify: years, quarters, months, weeks, days, hours, minutes, or seconds. How to generate days, weeks, or months between two dates in Oracle Database June 1, 2021 | 25 minute read Chris Saxon Developer Advocate There are. The date argument is a DATE value (or an expression that resolves to a DATE value) that should be rounded. In the empty box, enter the date format that you want to use. 一重引用符で囲んだ'YYYY-MM-DD[*HH:MI[:SS]]'形式の文字列(*はコロン(:)または空白でも可)、または現在の日付を返す引用符なしの@DATENOW. Improve this question. Converting a raw number of days into a number of weeks and days is pretty simple. The syntax for using the DATEDIFF function in Google BigQuery looks like the following:. For example, with some sample dates: select months_between (date '2015-03-19', date '2012-01-06') as month_diff from dual; MONTH_DIFF ---------- 38. Month-difference between any given two dates: Have a look at the TIMESTAMPDIFF () function in MySQL. DATEDIFF with examples DATEDIFF function accepts 3 parameters, first is datepart (can be an year, quarter, month, day, hour etc. If date1 is earlier than date2, then the result is negative. 9. How can I calculate the date difference between these 2 columns? sql; sql-server-2008; t-sql; datediff. Syntax. メンバーの日. it does not give me the records marked with a date '17-JAN-02'. Date Interval Calculation: The number of specified date parts between two provided dates is found using the DATEDIFF () method. g. I tried this selectExample: Oracle MONTHS_BETWEEN() Function - w3resourceHow to calculate age in T-SQL with years, months, and days. End Function. This field level rule lets you display the difference between two dates. Syntax. Step 4: Change Data Type. sql. select datediff (q,'03-30-2005','04-01-2005') will return 1. And then we need to convert the output of DATEPART to a 2-digit month number. Oracle Help Center - MONTHS_BETWEENyou ca also use LAG analytical function to get the desired results as : Suppose below is your input table: id account_number account_date 1 1001 9/10/2011 2 2001 9/1/2011 3 2001 9/3/2011 4 1001 9/12/2011 5 3001 9/18/2011 6 1001 9/20/2011 select id,account_number,account_date, datediff(day,lag(account_date,1) over (partition by. idUsage Notes¶. datediff ('MONTH', pr. numeric-expression. Table 9. Sorted by: 0. In pseudocode I would do: offset = ( (today. SQL was invented in the 1970s by IBM Computer Scientists. Then, we need a 2-digit month string. Asked 6 years, 5 months ago. I want get number of day difference between that date and date of today. The %DateAdd meta-SQL function returns a date by adding add_days to date_from. Share. SELECT DATEADD(WEEK, DATEDIFF(WEEK,0,GETDATE()),-3) Executes. 構文 @DATEDIFF (' difference ', ' date ', ' date ') difference. Would give you rows where date2 (the later date) is 60 to 90 days later than date1. Oracle SQL time difference in HH:MM:SS. (The valid formats 1,7,10,11 will be described later. StartTime: 2022-27-27 14:00:00 EndTime:2022-12-12 19:30:00 Firstly, to find the time difference, we will use. Learn how to use The SQL Server DATEDIFF() Function to return the difference between two dates. Thanks in advance for any help; this has been driving us crazy for a few months now. Order your results by the number of years employed. So it's not an accumulative difference, it's only when a date is within a smaller month. 242199 assumes that you want the number of solar years between 00:00 on the first date and 00:00 on the second date, to 9 significant figures. Share. , year, quarter, month, day, hour, minute, second), startdate is the starting date or time, and enddate is the ending date or time. ) Startdate = 2014-04-03 enddate = 2013-04-03 Result should be 12 as OP said. So I am porting many SQL Procedures to Oracle. E. Expressions that return a value of any of the following built-in data types: a date, a timestamp, a character string, or a graphic string. 18. For example, the function considers each of the following pairs of dates/timestamps to be exactly 1. Tom: 1. CODE = 'CONTACT_CLIENT' THEN a. As another option you could use the months_between () function, and manipulate the value that gives you into the three. I want to convert this number to years,Months,and Days. Note that SQL Server DATEDIFF(month, date2, date1) function does not return exactly the same result, and you have to use an user-defined function if you need to fully emulate the Oracle MONTHS_BETWEEN function (see UDF's code below). select S. Sep 16, 2015 at 5:55. Try SELECT SYSTIMESTAMP + INTERVAL '5' MINUTE, SYSTIMESTAMP + 5 / 24 / 60 to convince yourself. Oracle Fusion Global Human Resources Cloud Service - Version 11. Base_DateDiff counts the number of days between the two dates. 指定した日付の差異。次の値が有効です。 DD: 差異を日数で計算します。. There are many tricks to generate rows in Oracle Database. Can be one of the following values:1 Answer. Getting the last 12 months from a specific date is easy and can be retrieved by the following command in SQL-server. You will see column tools as one of the tabs. Then it subtracts a year if the birthdate hasn't passed. 1. There are two methods to achieve this. 0. Viewed 2k times 1 I need to calculate the number of days between two dates as decimal, excluding the weekends and holidays by using a custom function in Oracle SQL. However, since you have known start- and end-dates then you can find the number of full years between the two bounds and then use an INTERVAL DAY TO. 0 and later: Fusion OTBI Analysis - How to Convert Date of Birth to Age. One way to get our “DateDiff” function to exclude holidays and weekends is to have a calendar table pre-populated with some or all the information you need, and then use that table to exclude the dates. montant_annuel = NEW. Months "m" Quarters "q" Years "y" firstWeekDay (default value is 1) is a parameter that can be used if you are returning the length of time in weeks. Modified 9 years ago. To get the number of month or day, you change the first argument to month or day as shown below: Notice that the DATEDIFF () function takes the leap year into account. Factor by 24 to get hours, 24*60 to get minutes, 24*60*60 to get seconds (that's as small as dates go). dp_monthは、入力日付を取得する月間の距離を返します。 (2006年10月) - 2005年6月= 16) dp_weekは、入力日付を取得する週間の距離を返します。 各標準カレンダ週は日曜日に始まり、7日にまたがるように定義されています。 (2006年10月10日 - 2005年6月14日= 69)The result only contains the year, month and day, not the time. An expression that returns a value that is a built-in SMALLINT or. As you can see it means that month. Each Standard calendar week is defined to start on Sunday and it spans 7 days. (floor ( (Base_DateDiff + 0 + Start_WeekDay) / 7)) counts the number of sundays. 510345 May 24 2006 — edited May 24 2006. I want to calculate the current Age from Date of Birth in my Oracle function. e. ) The dates and their formats are separated by a comma (,) and are defined in the Data field of the. last_day (feb) to last_day (mar) is also commonly accepted as a "month". DP_QUARTER returns the distance between the quarters capturing the input dates. event_id, evnt. - Find the “date_diff” in minutes and add it with the “date_diff” in hours and the “date_ diff” in days. A number representing the input date between January 1, 1970 and Dec 31, 2037. The solution takes as base the first known date by SQL Server (1900-01-01). Viewed 3k times 0 I have table called C_Order. SELECT DATEADD(MONTH, DATEDIFF(MONTH, 0, GETDATE()), 0) As First_Of_Current_Month , DateAdd(dd, -1, DateAdd(mm, DateDiff(mm, 0, GETDATE()) +1, 0)) As Last_Of_Current. · User1416329745 posted ANSI SQL 1992. 2. id = tp. 365 / 365. Apart from using Joda time which seems to be the the favorite suggestion I'd offer the following snippet: public static final int getMonthsDifference (Date date1, Date date2) { int m1 = date1. 1. See the following conditions: If date1 is later than date2, then the result is positive. Viewed 2k times. DATEDIFF (MONTH, DATEADD (DAY,-DAY (startDate)+1,startDate),DATEADD (DAY,-DAY (startDate)+1,endDate)) Share. Subtracting two dates will return if and only if they are the same year, the same month, the same day, the same hour, the same minute, and the same second. And determining if the date falls on a holiday (by querying against your holiday table) should be trivial. In PostgreSQL there are basically 2 functions to do the same, as we have both date_part and extract: SELECT current_date AS ACTUAL_DATE, EXTRACT (DAY FROM current_date) AS ACTUAL_DAY, EXTRACT (MONTH FROM current_date) AS ACTUAL_MONTH, EXTRACT (YEAR FROM current_date) AS ACTUAL_YEAR. 2. The following example returns 2 for the months between the two dates:. 1. , YEAR, MONTH, DAY,. g. I recommend you have a stab yourself. id = al. ORA-00937 when calculating a sub-value in an aggregate select statement. The default is date format 1. DATEDIFF is a common function in the SQL Server to find the number of days between two dates. The weekday (dw) datepart returns a number that. PROJECTID, PROJ_TASK. This field level rule lets you display the difference between two dates. I am adding filter to OTBI report and want system to take first and last date of current month automatically. Using DbFunctions, accessed via EF. select datediff (q,'03-30-2005','04-01-2005') will return 1. Consider SQL Server function to calculate the difference between 2 dates in months: SQL Server : -- Difference between Oct 02, 2011 and Jan 01, 2012 in months SELECT DATEDIFF ( month, '2011-10-02', '2012-01-01') ; -- Result: 3. Columns c ) n cross join (select cast ('2001-01-01' as date) firstdate) const. InDays)) % (Pattern. It has been tested on a wide range of years (including leap ones) and more than 700k combinations of dates (including end of every months). The following example illustrates how to use the. then just use it in the script eg. (Oct 2006 - June 2005 = 16) DP_WEEK returns the distance between the weeks capturing the input. You can use this methodology to determine the first day of 3 months ago, and the last day of the previous month: select DATEADD (MONTH, DATEDIFF (MONTH, 0, GETDATE ())-3, 0) --First day of 3 months ago select DATEADD (MONTH, DATEDIFF (MONTH, -1, GETDATE ())-1, -1) --Last Day of previous month. 997268. Hi Ive been having an issue with getting the correct difference in a date from the current month not including the day. So, the difference between Jan 1 20015 and Dec 31 2016 is 1 year. The system calculates the number of complete months between given dates. Can Any one help me please. SELECT DATEDIFF (second, '2019-12-31 23:59:59', '2020-01-01 00:00:00'); A value of 1 is returned because the boundary of seconds is. Asked 9 years, 7 months ago. So you just have to multiply to get the result in minutes instead: SELECT (date2 - date1) * 24 * 60 AS minutesBetween FROM. 32 illustrates the behaviors of the basic arithmetic operators ( +, *, etc. SELECT DATEADD (month, 1, '20220730'); The below DATEADD will add 1 year to the provided date value, the year changed from 2022 to 2023. 1. Actually I have created a function for this but that quite complex . User-1629274867 posted Hi, I have replaced MS Oracle Client with OPD. Ecco una semplice funzione per calcolare la differenza tra due date. NET and i have faced several problems that i could fix but i couldn't fix the following: I have a stored procedure that takes date in parameters The stored procedures calls to_date with the format : MM/DD/YY HH:MI:SS AM The. Again, the expected results would be a value of 1. So, for example: WHERE date2 - date1 BETWEEN 60 AND 90. DATEADD ('week', 1, [due date]) Add 280 days to the date February 20, 2021. This post has been answered by BluShadow on Nov 18 2010. I tried this in a query. 3. There is no datediff in Oracle. SELECT DATEADD ( quarter, DATEDIFF. 4193548. Then use these rules to set the column values: Start date: for the first row, return the input date; otherwise return the first of the month; End date: get the month start for the next row and subtract one day from it. SELECT DATEDIFF (month,'2011-03-07' , '2021-06-24'); In this above example, you can find the number of months between the date of starting and ending. How to calculate days difference between two dates without leap year (365 days each year)? Thank you so much! I am new to Oracle Community Support, and I assumed that if I posted question in Oracle under SQL and PL/SQL, people would understand what I need. The MONTHS_BETWEEN function returns an estimate of the number of months between two arguments. Application. 9. Calculate how many years have passed: given year - 1900 2. The next example will show the differences between two dates for each specific datapart and abbreviation. I want something like this. SQL is also known as Structured Query Language. 3. Asked 9 years, 3 months ago. StartDate, SYSDATE) you would use: MONTHS_BETWEEN (pr. Label the column Years worked. If the endDate has a day part less than startDate, it will get pushed to the previous month, thus datediff will give the correct number of months. DateDiff. g. Then it would also be helpful to be able to remove holidays from this. The return type is always DATE, regardless of the datatype of date. sql. date_to) * 2) - CASE WHEN DATEPART(DW, evnt. Goal. Modified 2 years, 9 months ago. Get the difference between datetimes in years, months, and days down to seconds. Sorted by: 193. Justin, the example which you gave, if that is the scenario I want the output as 1. The following example calculates the months between two dates: SELECT MONTHS_BETWEEN (TO_DATE ('02-02-1995','MM-DD-YYYY'), TO_DATE ('01-01. DaysInYear Returns the number of days in the specified year. It works if my beginning date is the first of january and the end date the 31st of December, but does not if it stars somewhere else during the year. DOW: returns the day of the week, between Sunday (0) and Saturday (6) DOY: returns the day of the year. I have a data field in my table that i would to use within my WHERE clause, to get the last 12 months dataset so for example, WHERE date between '20110323' and '20100323' Is this possible? I know I have to use something like GETDATE() or something but not quite sure how to incorporate this. I need the Oracle equivalent to the SQL Server DATEDIFF function to compute the difference between two dates. The former produces a number representing the count of days between the two dates, while the latter produces an interval representation of the. ;-). This function is used to find the difference between two specified values of date. The @DATEDIFF calculation function for Essbase returns the difference between two input dates.